RIB · English Edition

对齐度简化V0

RIB(中文) · RIB简单设计 · POSA和对齐

好,那我给你一版真的可以写进代码的“确定性版本”,

只在可编程、可验证、无歧义的边界内干三件事:

关系(Relation)– 承诺(Commitment)– 一致性检查(Consistency)

我用接近代码的形式给你一套 v0 规范,你以后直接让工程师照着实现就行。

0. 边界先卡死(很重要)

这个版本不碰自然语言、情绪、embedding,只处理:

一切判断只基于这些结构化数据 → 100% 确定性,可验证,可审计。

1. 核心数据结构(可直接当 schema 用)

# 实体:用户 / 任务 / 模块 / 团队等

class Entity:

id: str # "user:sky", "task:123", "mod:flux_econ"

kind: str # "user" | "task" | "module" | "team" ...

# 关系:只允许 6 种

RType = Literal["is_a", "part_of", "depends_on", "supports", "contradicts", "belongs_to"]

class Relation:

src: str # Entity.id

rtype: RType

dst: str # Entity.id

# 官方 ISO 关系图(系统“真相”)

ISO_Graph: set[Relation]

# 承诺:谁在什么时间前要对哪个对象做什么事,并质押了多少

class Commitment:

id: str

actor: str # Entity.id (user/agent)

target: str # Entity.id (task/module/PR)

action: str # "implement" | "review" | "deploy" | ...

due_fold: int # 截止 Fold

staked_power: int

staked_flux: int

# 执行日志:实际发生的动作

class ExecutionEvent:

id: str

actor: str # Entity.id

target: str # Entity.id

action: str # 必须来自有限动作集

fold: int

status: str # "success" | "fail"

2. 关系对齐检查:RAS(纯结构)

对任意一条观察到的关系 ObservedRel(src, rtype_obs, dst):

def relation_alignment(src, rtype_obs, dst) -> int:

"""

return ∈ {-3, -2, -1, 0, 1, 2, 3}

"""

score = 0

# R1: 类型是否与官方 ISO 一致

iso_rel = find_iso_relation(src, dst) # 如果有定义,否则 None

if iso_rel:

if iso_rel.rtype == rtype_obs:

score += 1

else:

score -= 1

# R2: 关系是否在白名单中

if rtype_obs in ["is_a", "part_of", "depends_on", "supports", "contradicts", "belongs_to"]:

score += 1

else:

score -= 1

# R3: 若是 depends_on,检查执行顺序是否符合依赖

if rtype_obs == "depends_on":

if executed_after(src, dst): # 从 ExecutionEvent 日志判断

score += 1

else:

score -= 1

return score

然后:

def RAS(actor: str) -> float:

# 统计该 actor 参与的所有关系使用(配置/声明/操作)

scores = [relation_alignment(r.src, r.rtype, r.dst)

for r in observed_relations_involving(actor)]

if not scores:

return 0.0

return sum(scores) / (3 * len(scores)) # 归一化到 [-1, 1]

3. 承诺一致性检查:ExecAlign(纯行为)

def commitment_alignment(c: Commitment) -> float:

"""

对单个承诺做一致性检查,返回 [-1,1]

"""

events = find_exec_events(actor=c.actor, target=c.target, action=c.action)

# 条件1:有没有在截止 Fold 前至少一次成功执行

done_in_time = any(e.status == "success" and e.fold <= c.due_fold for e in events)

# 条件2:有没有明显“反向行为”(比如撤销/破坏)

sabotage = any(e.action == "revert" and e.fold <= c.due_fold for e in events)

score = 0

if done_in_time:

score += 1

else:

score -= 1

if sabotage:

score -= 1

return max(-1.0, min(1.0, score)) # [-1,1]

对某个 actor 的整体承诺一致性:

def ExecAlign(actor: str) -> float:

cs = commitments_by(actor)

if not cs:

return 0.0

scores = [commitment_alignment(c) for c in cs]

return sum(scores) / len(scores) # [-1,1]

4. 成本承诺:StakeAlign(敢不敢用 Power/Flux 说话)

def StakeAlign(actor: str) -> float:

cs = commitments_by(actor)

if not cs:

return 0.0

total_power_staked = sum(c.staked_power for c in cs)

total_flux_staked = sum(c.staked_flux for c in cs)

# 和全网平均比,简单归一化一下

avg_power = network_avg_power_stake()

avg_flux = network_avg_flux_stake()

# 简单粗暴:高于平均 → 正,高很多 → 接近 1,远低于平均 → 负

p_ratio = (total_power_staked / avg_power) if avg_power > 0 else 0

f_ratio = (total_flux_staked / avg_flux) if avg_flux > 0 else 0

raw = 0.5 * p_ratio + 0.5 * f_ratio

# 把 raw 映射到 [-1,1],例如截断在 [0,2]

if raw >= 2:

return 1.0

elif raw <= 0:

return -1.0

else:

return raw - 1.0 # raw∈[0,2] → [-1,1]

5. 对齐度 H:完全结构化、可验证

这里先不引入语义 POSA,只用“关系 + 承诺 + 成本” 三个维度:

def H(actor: str) -> float:

s_rel = RAS(actor) # 结构对齐 [-1,1]

s_exec = ExecAlign(actor) # 承诺兑现 [-1,1]

s_stake = StakeAlign(actor) # 成本承诺 [-1,1]

alpha, beta, gamma = 0.4, 0.4, 0.2 # 初始权重

h = alpha*s_rel + beta*s_exec + gamma*s_stake

return max(-1.0, min(1.0, h))

这就是你要的“确定性边界内的可验证对齐度”,完全可编程,无需 NLP。

6. H 如何喂给 Power / Flux / PoCW(更新规则)

Power 解锁:

def power_unlock_per_fold(actor: str) -> int:

P_base = 100 # 系统常数

h = H(actor)

return int(P_base * (0.5 + 0.5*h)) # H=1 →100, H=0→50, H=-1→0

PoCW 有效工作量:

def effective_work(actor: str, W_raw: float) -> float:

h = H(actor)

h_pos = max(0.0, h)

return W_raw * (0.5 + 0.5*h_pos) # H≤0 →0.5, H=1→1.0

惩罚(对齐造假时触发):

def punish(actor: str, committed_power: int, committed_flux: int):

lambda_P, lambda_F, eps = 0.2, 0.2, 0.1

burn_power(actor, int(committed_power * lambda_P))

burn_flux(actor, int(committed_flux * lambda_F))

decrease_H(actor, eps) # H_i ← H_i - eps(内部有界到 [-1,1])

7. 可验证性:为什么这是“deterministic & verifiable”

在这个边界内,治理 = 一套可审计的程序。

关系-承诺-一致性检查 → 全部变成确定的计算。

如果你愿意,下一步我可以: